Trang chủ » A fair coin is tossed 10 times. Then the probability that two heads do not occur consecutively is a. 7//64 b. 1//8 c. 9//16 d. 9//64

# A fair coin is tossed 10 times. Then the probability that two heads do not occur consecutively is a. 7//64 b. 1//8 c. 9//16 d. 9//64

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similarly we are having a phosphorus 333 would be equal 283123 12 so that would be equal to its 35656 upon to raise to the world power 10 similarly FIFA 20 7C 41 B to raise to the power 4 and 1 by 2 lift to the exponent 6 which comes out to be 7647 c4s 3535 to restore the world power 10 and the last EP 555 would be 651 by to ability 5 and 1 by 2 world power 5 so that would come out to be 60586 only sol 6.2 slipstream to the exponent 10 superhero lyrics in the question we have clearly mentioned that is greater than B if there were any five cases thus what would be here so that would be the full probability with BP 0 + 51 + B2 + B3 + T4 plus P6 on it would be up to 45 so here it is P5 it is P5 that would be equal to in the denominator It is seen that is to raise to the world power 10 some writing down and a dramatic tourist to the power 10 in the numerator it is 1 + 10 + 36 + 56 + 35 + 6 after accession it comes out to be 144 upon 2 lift to the power 10 so solving it it is if I ‘ll be multiplied with 10 clock time so that is sol I can stated as 144 orient tourist ability 32 32 32 now we know that a 16 lines are 14459 saffat 14462 the 32 dangerous left 9.64 this is the probability lashkar-e-taiba ‘s have a search at your options so it is 9.64 it means adoption is the decline answer I hope six Nations cup

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