SOLVED:1.What is the probability of obtaining ten heads in a row when flipping a coin? Interpret this probability. The probability of obtaining ten heads in a row when flipping a coin is ______? (Roun

Video Transcript

Hello everyone we are going to solve vacation in this question we have three parts for the first one We have to find the probability of getting pinheads in a row. And besides we have to find expect Well you when consequence is repeated When even this reputed 10,000 times. That means that N. is equals to 10,000. so starting with the solution of this as we know the probability of getting the head in it, throw of mint 0.5 Show the probability of getting 10 heads in a row Is equals to 0.5 raised to the baron 10 which is equals to 0.00098. so this is the answer for the probability of getting 10 heads in a course. now we calculate expected values. so expected count of events is equals two and multiplied by P. So hera and it ‘s 10,000 And PV calculated us 0.00098 Which is equals to 9.8 which is approximately 10 times. So this is the answer for expected value. now in the second region of this question we are given This is our second part. We are giving the probability of examination is negative veto when antibody is not stage it is not portray And this is equals to 0.998. And the probability that the test is cocksure when antibody is not present and this is equals to 0.002. then in this we have to find two parts. In a part we have to find the probability the test comes negative four, five people. And in the second part, that is be share. We have to find the probability That at least one positive test one incontrovertible. so now calculating this for a pot solving a part, we have to calculate the probability of this becomes damaging for five people, four five people. So this is equals to 0.998 raised to the par five as there are five people. So this is equals to 0.99004. now, in the second part, that is this is the answer for the air separate. now in the second part, that is be separate we have to find probability of at least one cocksure. So for now at least one positivist, this is adequate to one minus probability not all not all positive Or we can see not all 1- the probability of not all negative. here we have probability of not all plus or we can say not wholly here we have one subtraction all minus, we can say all negative. So the probability for all veto is this is 0.99004. When we calculated this, we found that this is equal to 0.00996 which is the answer for B Party. now in 3rd wonder in 3rd motion of this, we are given that there are golf balls and third gear we are given there are golf balls, seven bowls are led, seven crimson balls, three yellow And 11 Orange Balls. And we have to find probability of getting either bolshevik or yellow ball. So we are representing our our is here. Read in Y is yellow. so for solving this probability for red or yellow is equal to probability of crimson plus probability of jaundiced as there is nothing common in these balls. So this is equal to true probability of spoke. There are seven crimson balls and total bowl at 21 plus probability of jaundiced. There are three yellow balls and the sum at 21. This comes out to be 10, divided by 21 watches equals to 0.476, which is the concluding answer for this. Thank you.

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