# SOLVED:Matching Probabilities Exercises 11-14, match the event with its probability: (a) 0.95 (b) 0.05 (c) 0.25 (d) 0 ML. You toss a coin and randomly select number from 0 t0 9. What is the probabilit

### Video Transcript

in this problem, we are given four questions and we have to match their answers from the given options. So let ‘s take the beginning question question # 11. In this question, we are told that a coin is tossed on, a random number is selected from 0 to 9 and we have to find the probability of tossing tails and selecting A three here. The probability B is given by probability of drawing a dock multiplied by probability of getting a tree. now for a coin there there are alone two outcomes. So the probability of drawing a narrative will be one divided by two, multiplied by probability here, the number three selected from 0 to 9, that means the probability will be one divided. By then On solving this, we get it ‘s rate equal to 0.05. That means option B is the correct answer for the first interview. The next interview question # 12 says That a random number generator choice number from 1 200 and we have to find the probability of selecting The number 1 53. But as we are told that the act generator merely selects the number from 1 200. That means the probability of drawing the number 153 is zero because this is not one of the outcomes from the generator. frankincense, option D is the correct answer for question # 12. in the future motion interrogate # 13, we are told that a dissenter randomly selected tour from four different doors from which only one of the doors doubles her money While the other three does leave her with no winnings. And we have to find the probability that she selects the doorway that doubles her money. That means probability P of winning is given by one divided by four because There is only one winning door between among the four different doors. And this is equal to 0.25, which means option. She is the right answer for interview number 13. In motion 14, we are told that five of the 100 DVRs are defective and we have to find the probability that a not defective DVR is selected here. The probability P is given by the count or not defective DVRs divided by the sum issue of DVRs. That means 100 minus five because five are bad divided by 100 because 100 are a total count of DVRs. This is equal to 95, divided by 100, Which is adequate to 0.95. This means choice A is the correct answer for the fourth question. That is motion number 14 and this is our solution

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